The Milwaukee Bucks won the NBA Draft Lottery on Tuesday night and will have the first pick for the June 28 draft. The Bucks, who were the NBA's sixth worst team during the regular season with a 30-52 mark, had 6.3 percent chance of winning coming in. Atlanta, the league's worst team at 13-69, had a 25-percent chance of winning the lottery, but will instead pick second. Milwaukee won its first lottery since 1994 when they selected Glenn Robinson. Portland also jumped from its original position, as it moved two spots to No. 3. The moves bumped the New Orleans Hornets from an expected two spot to the fourth pick, while the third worst team last season, the Charlotte Bobcats, moved down to five. The Utah Jazz also slipped from four to six. From there everything else went as expected. Toronto, New York, Golden State and the Los Angeles Lakers round out the top 10. Orlando, the LA Clippers, Charlotte and Minnesota will select 11 through 14, respectively. With the top pick Milwaukee could select Utah center Andrew Bogut, North Carolina forward Marvin Williams or Wake Forest point guard Chris Paul - widely regarded as the three best players available This system has been in place since June of 1984 when the NBA Board of Governors voted to adopt a lottery system among the non-playoff teams to determine their order of selection in the first round of the NBA Draft beginning in 1985. From 1966 through 1984, the teams that finished with the worst records in each conference participated in a coin flip to determine which team would draft first. The remaining teams picked in inverse order of their won-lost records. The New York Knicks won the first-ever lottery and used their No. 1 selection on Georgetown center Patrick Ewing.